In this article we are sharing AFCAT Exam Topic Based Important Sample Question Answer Set 2, we have already published set 1.
AFCAT Exam Topic Based Important Sample Question Answer Set 2
| 1. There were 24 students in a class. One of them, who was 18 years old, left the class and his place was filled up by a new comer. If the average of the class was thereby lowered by 1 month, the age of new comer is- | ||
| a. 14 years | ||
| b. 15 years | ||
| c. 16 years | ||
| d. 17 years | ||
| Solution. Let new comer age was x. Average age decreased by = 1 month = 1/12 years.  No. of students in class * aged decreased = difference of replacement 24 * 1/12 = 18 – x |
||
| Answer. c | ||
| 2. A bag contains 25 paise, 50 paise and 1 Rs coins. There are 220 coins in all and the total amount in the bag is Rs . 160. If there are thrice as many 1 Rs. Coins as there are 25 paise coins, then what is the number of 50 paise coins? | ||
| a. 60 | ||
| b. 40 | ||
| c. 120 | ||
| d. 80 | ||
Solution. 
Let the number of 25 paise coins = x Then number of 50 paise coin = 3x And let the number of 50 pasie coin = y
Now,
Solving (1) and (2) we get x = 40 and y = 60 |
||
| Answer. a | ||
| 3. The average weight of 5 men is increased by 2 Kg when one of the men whose weight is 60 Kg is replaced by a new man. The weight of the new man is | ||
| a. 50 Kg | ||
| b. 65 Kg | ||
| c. 68 Kg | ||
| d. 70 Kg | ||
| Solution. (60+a+b+c+d)/5 = W ——(i)
(n+a+b+c+d)/5 = W+2 —–(ii) (ii) – (i) n-60 = 10 n = 70 Kg |
||
| Answer. d | ||
| 4. If a sum becomes double in 16 years, how many times will it be in 8 years? | ||
| a. 1(1/2) times | ||
| b. 1(1/3) times | ||
| c. 1(3/4) times | ||
| d. 1(1/4) times | ||
| Solution. Let the sum be S
Sum in 16 yrs —— 2S increase is 100 % so for 8 yrs increase will be 50 % |
||
| Answer. a | ||
| 5. Srinivasan invests two equal amounts in two banks giving 8% and 12% rate of interest respectively. At the end of year the interest earned is Rs 1500. Find the sum invested in each. | ||
| a. 8500 | ||
| b. 15000 | ||
| c. 7500 | ||
| d. 17000 | ||
| Solution. One must understand that Rs 1500 is the total interest earned on two unknown but equal amounts at 8% and 12%.
Let ‘y’ be the amounts then, adding the interests
|
||
| Answer. c | ||
| 6. In a mixture of 60 litres, the ratio of milk and water is 2:1. What amount of water must be added to make the ratio of milk and water as 1:2 ? | ||
| a. 42 Litres | ||
| b. 56 Litres | ||
| c. 60 Litres | ||
| d. 77 Litres | ||
| Solution. Water in initial mixture
Milk in the initial mixture
Let ‘x’ be the water that is added later to change the ratio
|
||
| Answer. c | ||
| 7. The salary of A & B together amounts to Rs.2000. A spends 95% of his salary and B 85% of his salary. If their savings are same what is the salary of A? | ||
| a. 750 | ||
| b. 1250 | ||
| c. 1500 | ||
| d. 1600 | ||
| Solution. (5/100) A = (15/100) B
A = 3B A + B = 2000 4B = 2000 => B = 500 A = 1500 |
||
| Answer. c | ||
| 8. How much time will it take for an amount of Rs.450 to gain Rs.81 as interest, if rate of interest is 4.5% p.a on simple interest? | ||
| a. 4.5 years | ||
| b. 3.5 years | ||
| c. 5 years | ||
| d. 4 years | ||
| Solution. PTR/100
Time = (100×81/ 450×4.5)years => 4 years. |
||
| Answer. d | ||
| 9. A loss of 19% on a shirt gets converted into a profit of 17% when the selling price is increased by Rs 162. What is the cost price of the shirt? | ||
| a. Rs 540 | ||
| b. Rs 450 | ||
| c. Rs 600 | ||
| d. Rs 360 | ||
| Solution. A change from 19% loss to 17% gain means a change of 36%
36% = 162
1% = 162/36
100% = 162/36 × 100 = 450 Rs |
||
| Answer. b | ||
| 10. If the selling price of an article is 4/3 of its cost price, the profit in transaction is | ||
| a. 16.75% | ||
| b. 20.50% | ||
| c. 25.50% | ||
| d. 33.33% | ||
| Solution. Lets assume CP as Rs.300/-
So SP will be 300 x (4/3) = Rs.400/- Profit = SP-CP= Rs.100/- ie if SP is 4/3=(1.3333) then CP will be 1 and profit will be 1.33333–1=0.3333 1/3 = 0.3333 |
||
| Answer. d | ||
| 11. If a/(a+b) = 17/23, what is (a+b)/(a-b) equal to? | ||
| a. 13/7 | ||
| b. 23/11 | ||
| c. 14/5 | ||
| d. 25/9 | ||
Solution. 
|
||
| Answer. b | ||
| 12. A sum of money is to be distributed among P, Q and R in the ratio of 6:19:7. If R gives Rs 200 from his share to Q. the ratio of P, Q and R becomes 3: 10:3, what is the total sum? | ||
| a. Rs 3200 | ||
| b. Rs 12800 | ||
| c. Rs 6400 | ||
| d. Data inadequate | ||
| Solution. Let the 6x, 19x and 7x be the money distributed among, P, Q and R respectively,
Hence, 6x + 19x + 7x = 32 x is the total amount of money
After R gives Rs 200 to Q, there ratio become 3x:10x:3x = 6x:20x:6x,
if we compare this ratio to the above ration we will see a change from 7x to 6x and 19x to 20x,
Hence there difference i.e x = 200,
Therefore the total amount of money = 32x = 32× 200 = 6400 Rs |
||
| Answer. c | ||
| 13. 75 pupils from a school appeared for an examination and 80% of them passed. Another school entered 10 more pupils than the first school and five pupils less than the first school passed. The pass % of in the second school was | ||
| a. 75% | ||
| b. 84% | ||
| c. 72% | ||
| d. 64.7% | ||
| Solution. Number of students who passed in the first school
75 x 0.8 = 60 Number of students who appeared for exam in the second case = 75 + 10 = 85. Number of students who passed from the second school is 5 less than the first school. 60 – 5= 55 Hence, the passing percentage of the second school
|
||
| Answer. d | ||
| 14. Find the average of all the numbers between 6 and 34 which are divisible by five. | ||
| a. 18 | ||
| b. 20 | ||
| c. 20 | ||
| d. 30 | ||
Solution.  |
||
| Answer. b | ||
15.  |
||
| a. 2 | ||
| b. 6 | ||
| c. 4 | ||
| d. 8 | ||
| Answer. c | ||
16. 
Which section is missing?
|
||
| a. A | ||
| b. B | ||
| c. C | ||
| d. D | ||
| Solution. C: added together, opposite segments contain six empty circles and three with a stripe | ||
| Answer. c | ||
| 17. Which is the odd one out?
|
||
| a. A | ||
| b. B | ||
| c. C | ||
| d. D | ||
| Solution. B: A is the same as F rotated, C is the same as G and E is the same as D | ||
| Answer. b | ||
18. 
Which is the missing tile?
|
||
| a. E | ||
| b. F | ||
| c. G | ||
| d. H | ||
| Solution. E: looking across, the long line is moving 45° clockwise at each stage and the small line 45° anti clockwise. Looking down, the reverse is happening. | ||
| Answer. a | ||
19. 
What comes next?
|
||
| a. A | ||
| b. B | ||
| c. C | ||
| d. D | ||
| Solution. C: the horizontal figure is disappearing by half a side at each stage and the vertical figure is appearing by half aside at each stage | ||
| Answer. c | ||
| 20. Which is the odd one out?
|
||
| a. C | ||
| b. D | ||
| c. E | ||
| d. F | ||
| Solution. E: in all the others the triangle is upside down | ||
| Answer. c | ||
