In this article we are taking most refined sample questions that are taken from math section of CDSÂ question paper and presenting it to you, so have a look and see if you are comfortable in solving these kind of questions then only you have any chance of clearing the CDSÂ exam.
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CDS 2 2017 Elementary Mathematics Exam Important Questions

1. If the roots of the equation are in the ration p:q, then is equal to |
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| a. 0 | ||
| b. 1 | ||
| c. 2 | ||
| d. 3 | ||
| Answer. a | ||
2. ![]() |
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| a. -15 | ||
| b. -5 | ||
| c. 0 | ||
| d. 5 | ||
| Answer. c | ||
3. ![]() |
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a. ![]() |
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b. ![]() |
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c. ![]() |
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d. ![]() |
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| Answer. c | ||
4. ![]() |
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| a. a+b+c | ||
| b. 3 | ||
| c. 1 | ||
| d. 0 | ||
| Answer. c | ||
5. ![]() |
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| a. p-q = 0 | ||
| b. p+q-2 = 0 | ||
| c. p+q-1 = 0 | ||
| d. p-q-1 = 0 | ||
| Answer. d | ||
6. ![]() |
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| a. 0 | ||
| b. 1 | ||
| c. 2 | ||
| d. 3 | ||
| Answer. a | ||
7. The sum and difference of two expression are and respectively. The HCF of two expressions will be |
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| a. (x+1) | ||
| b. (x-1) | ||
| c. (3x+7) | ||
| d. (2x-3) | ||
| Answer. b | ||
8. If (s-a)+(s-b)+(s-c) = s, then the value of will be |
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| a. 3 | ||
| b. 1 | ||
| c. 0 | ||
| d. -1 | ||
| Answer. b | ||
9. Â ![]() |
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| a. 1 | ||
| b. 9 | ||
| c. 10 | ||
| d. 13 | ||
| Answer. c | ||
| 10. Let p and q be non-zero integers. Consider the polynomial A(x) = x^2 + px+q It is given that (x – m) and (x – km) are simple factors of A(x), where m is a non-zero integer and k is a positive integer, k ≥ 2. Which one of the following is correct? | ||
| a. |
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| b. |
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| c. |
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| d. |
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| Answer. b | ||
| 11. Let m be a non-zero integer and n be a positive integer. Let R be the remainder obtained on dividing the polynomial X^n + M^n by (x-m). Then | ||
| a. R is a non-zero even integer | ||
| b. R is odd, if m is odd | ||
| c. R = s^2 for some integer s, if it is even | ||
| d. R = t^3 for some integer t, if 3 divides n | ||
| Answer. c | ||
12. ![]() |
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| a. 7 | ||
| b. 5 | ||
| c. 3 | ||
| d. 1 | ||
| Answer. b | ||
13. if the linear factors of  are p and q, then p+q is equal to |
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| a. (x-1)(a+1) | ||
| b. (x+1)(a+1) | ||
| c. (x-1)(a-1) | ||
| d. (x+1)(a-1) | ||
| Answer. d | ||
14. If then is equal to (given that b≠0) |
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| a. 0 | ||
| b. 1 | ||
| c. ab | ||
| d. 2ab | ||
| Answer. a | ||
15. ![]() |
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| a. 7 | ||
| b. 9 | ||
| c. 11 | ||
| d. 13 | ||
are in the ration p:q, thenÂ
is equal to








and
respectively. The HCF of two expressions will be
will be

 are p and q, then p+q is equal to
then
is equal to (given that b≠0)















