Search
Close this search box.

NDA 1 2017 Maths Question Paper and Sample Questions

Aspirants willing to join Indian Armed Forces and have applied for upcoming NDA (national Defence Academy) entrance exam are now in the process of preparation for the NDA written exam....

Aspirants willing to join Indian Armed Forces and have applied for upcoming NDA (national Defence Academy) entrance exam are now in the process of preparation for the NDA written exam. So for the purpose of preparation, candidates are searching for previous year’s NDA exam papers. In this article we are sharing NDA 1 2017 Maths Question Paper and Sample Questions.

NDA Coaching

NDA 1 2017 Maths Question Paper and Sample Questions

NDA 1 2017 Maths Question Paper and Sample Questions

Download Question Paper

Click on the link given below to download NDA 1 2017 Maths Question Paper

NDA 1 2017 MATH QUESTION PAPER PDF

Download Answer Key

Click on the link given below to download NDA 1 2017 Maths Question Paper  Answer Key

Answer Key

Sample Questions

1. If the roots of the equation «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi mathvariant=¨normal¨»lx«/mi»«mn»2«/mn»«/msup»«mo»+«/mo»«mi mathvariant=¨normal¨»mx«/mi»«mo»+«/mo»«mi mathvariant=¨normal¨»m«/mi»«moȤnbsp;«/mo»«mo»=«/mo»«moȤnbsp;«/mo»«mn»0«/mn»«/math» are in the ration p:q, then Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msqrt»«mfrac»«mi mathvariant=¨normal¨»p«/mi»«mi mathvariant=¨normal¨»q«/mi»«/mfrac»«/msqrt»«mo»+«/mo»«msqrt»«mfrac»«mi mathvariant=¨normal¨»q«/mi»«mi mathvariant=¨normal¨»p«/mi»«/mfrac»«/msqrt»«mo»+«/mo»«msqrt»«mfrac»«mi mathvariant=¨normal¨»m«/mi»«mi mathvariant=¨normal¨»l«/mi»«/mfrac»«/msqrt»«/math» is equal to
a. 0
b. 1
c. 2
d. 3
Answer. a
2. «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi mathvariant=¨normal¨»If«/mi»«mo»§nbsp;«/mo»«msqrt»«mrow»«mn»3«/mn»«msup»«mi mathvariant=¨normal¨»x«/mi»«mn»2«/mn»«/msup»«mo»-«/mo»«mn»7«/mn»«mi mathvariant=¨normal¨»x«/mi»«mo»-«/mo»«mn»30«/mn»«/mrow»«/msqrt»«mo»§nbsp;«/mo»«mo»-«/mo»«mo»§nbsp;«/mo»«msqrt»«mrow»«mn»2«/mn»«msup»«mi mathvariant=¨normal¨»x«/mi»«mn»2«/mn»«/msup»«mo»-«/mo»«mn»7«/mn»«mi mathvariant=¨normal¨»x«/mi»«mo»-«/mo»«mn»5«/mn»«/mrow»«/msqrt»«mo»§nbsp;«/mo»«mo»=«/mo»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»x«/mi»«mo»-«/mo»«mn»5«/mn»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»has«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»§#945;«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»and«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»§#946;«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»as«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»its«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»roots«/mi»«mo»,«/mo»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»then«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»the«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»value«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»of«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»§#945;§#946;«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»is«/mi»«/math»
a. -15
b. -5
c. 0
d. 5
Answer. c
3. «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi mathvariant=¨normal¨»if«/mi»«mo»§nbsp;«/mo»«mfrac»«mi mathvariant=¨normal¨»p«/mi»«mi mathvariant=¨normal¨»x«/mi»«/mfrac»«mo»+«/mo»«mfrac»«mi mathvariant=¨normal¨»q«/mi»«mi mathvariant=¨normal¨»y«/mi»«/mfrac»«mo»=«/mo»«mi mathvariant=¨normal¨»m«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»and«/mi»«mo»§nbsp;«/mo»«mfrac»«mi mathvariant=¨normal¨»q«/mi»«mi mathvariant=¨normal¨»x«/mi»«/mfrac»«mo»+«/mo»«mfrac»«mi mathvariant=¨normal¨»p«/mi»«mi mathvariant=¨normal¨»y«/mi»«/mfrac»«mo»=«/mo»«mi mathvariant=¨normal¨»n«/mi»«mo»,«/mo»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»then«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»what«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»is«/mi»«mo»§nbsp;«/mo»«mfrac»«mi mathvariant=¨normal¨»x«/mi»«mi mathvariant=¨normal¨»y«/mi»«/mfrac»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»equal«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»to«/mi»«mo»?«/mo»«/math»
a. «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi mathvariant=¨normal¨»n«/mi»«mi mathvariant=¨normal¨»p«/mi»«mo»+«/mo»«mi mathvariant=¨normal¨»m«/mi»«mi mathvariant=¨normal¨»q«/mi»«/mrow»«mrow»«mi mathvariant=¨normal¨»m«/mi»«mi mathvariant=¨normal¨»p«/mi»«mo»+«/mo»«mi mathvariant=¨normal¨»n«/mi»«mi mathvariant=¨normal¨»q«/mi»«/mrow»«/mfrac»«/math»
b. «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi mathvariant=¨normal¨»n«/mi»«mi mathvariant=¨normal¨»p«/mi»«mo»+«/mo»«mi mathvariant=¨normal¨»m«/mi»«mi mathvariant=¨normal¨»q«/mi»«/mrow»«mrow»«mi mathvariant=¨normal¨»mp«/mi»«mo»-«/mo»«mi mathvariant=¨normal¨»nq«/mi»«/mrow»«/mfrac»«/math»
c. «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi mathvariant=¨normal¨»np«/mi»«mo»-«/mo»«mi mathvariant=¨normal¨»mq«/mi»«/mrow»«mrow»«mi mathvariant=¨normal¨»mp«/mi»«mo»-«/mo»«mi mathvariant=¨normal¨»nq«/mi»«/mrow»«/mfrac»«/math»
d. «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mi mathvariant=¨normal¨»np«/mi»«mo»-«/mo»«mi mathvariant=¨normal¨»mq«/mi»«/mrow»«mrow»«mi mathvariant=¨normal¨»mp«/mi»«mo»+«/mo»«mi mathvariant=¨normal¨»nq«/mi»«/mrow»«/mfrac»«/math»
Answer. c
4. «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnalign=¨left¨ rowspacing=¨0¨»«mtr»«mtd»«mi mathvariant=¨normal¨»If«/mi»«mo»§nbsp;«/mo»«msup»«mi mathvariant=¨normal¨»a«/mi»«mn»2«/mn»«/msup»«mo»-«/mo»«mi mathvariant=¨normal¨»by«/mi»«mo»-«/mo»«mi mathvariant=¨normal¨»cz«/mi»«mo»§nbsp;«/mo»«mo»=«/mo»«mo»§nbsp;«/mo»«mn»0«/mn»«mo»,«/mo»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»ax«/mi»«mo»-«/mo»«msup»«mi mathvariant=¨normal¨»b«/mi»«mn»2«/mn»«/msup»«mo»+«/mo»«mi mathvariant=¨normal¨»cz«/mi»«mo»§nbsp;«/mo»«mo»=«/mo»«mo»§nbsp;«/mo»«mn»0«/mn»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»and«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»ax«/mi»«mo»+«/mo»«mi mathvariant=¨normal¨»by«/mi»«mo»-«/mo»«msup»«mi mathvariant=¨normal¨»c«/mi»«mn»2«/mn»«/msup»«mo»§nbsp;«/mo»«mo»=«/mo»«mo»§nbsp;«/mo»«mn»0«/mn»«mo»,«/mo»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»then«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»the«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»value«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»of«/mi»«/mtd»«/mtr»«mtr»«mtd/»«/mtr»«mtr»«mtd»«mfrac»«mi mathvariant=¨normal¨»x«/mi»«mrow»«mi mathvariant=¨normal¨»a«/mi»«mo»+«/mo»«mi mathvariant=¨normal¨»x«/mi»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mi mathvariant=¨normal¨»y«/mi»«mrow»«mi mathvariant=¨normal¨»b«/mi»«mo»+«/mo»«mi mathvariant=¨normal¨»y«/mi»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mi mathvariant=¨normal¨»z«/mi»«mrow»«mi mathvariant=¨normal¨»c«/mi»«mo»+«/mo»«mi mathvariant=¨normal¨»z«/mi»«/mrow»«/mfrac»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»will«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»be«/mi»«/mtd»«/mtr»«/mtable»«/math»
a. a+b+c
b. 3
c. 1
d. 0
Answer. c
5. «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnalign=¨left¨ rowspacing=¨0¨»«mtr»«mtd»«mi mathvariant=¨normal¨»If«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»the«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»equations«/mi»«mo»§nbsp;«/mo»«msup»«mi mathvariant=¨normal¨»x«/mi»«mn»2«/mn»«/msup»«mo»-«/mo»«mi mathvariant=¨normal¨»px«/mi»«mo»+«/mo»«mi mathvariant=¨normal¨»q«/mi»«mo»§nbsp;«/mo»«mo»=«/mo»«mn»0«/mn»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»and«/mi»«mo»§nbsp;«/mo»«msup»«mi mathvariant=¨normal¨»x«/mi»«mn»2«/mn»«/msup»«mo»+«/mo»«mi mathvariant=¨normal¨»qx«/mi»«mo»-«/mo»«mi mathvariant=¨normal¨»p«/mi»«mo»§nbsp;«/mo»«mo»=«/mo»«mo»§nbsp;«/mo»«mn»0«/mn»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»have«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»a«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»common«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»root«/mi»«mo»,«/mo»«mo»§nbsp;«/mo»«/mtd»«/mtr»«mtr»«mtd»«mi mathvariant=¨normal¨»then«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»which«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»one«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»of«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»the«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»following«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»is«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»correct«/mi»«mo»?«/mo»«/mtd»«/mtr»«/mtable»«/math»
a. p-q = 0
b. p+q-2 = 0
c. p+q-1 = 0
d. p-q-1 = 0
Answer. d
6. «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi mathvariant=¨normal¨»If«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»x«/mi»«mo»§nbsp;«/mo»«mo»=«/mo»«mo»§nbsp;«/mo»«msup»«mn»2«/mn»«mfrac»«mn»1«/mn»«mn»3«/mn»«/mfrac»«/msup»«mo»+«/mo»«msup»«mn»2«/mn»«mrow»«mo»-«/mo»«mfrac»«mn»1«/mn»«mn»3«/mn»«/mfrac»«/mrow»«/msup»«mo»,«/mo»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»then«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»the«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»value«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»of«/mi»«mo»§nbsp;«/mo»«mn»2«/mn»«msup»«mi mathvariant=¨normal¨»x«/mi»«mn»3«/mn»«/msup»«mo»-«/mo»«mn»6«/mn»«mi mathvariant=¨normal¨»x«/mi»«mo»-«/mo»«mn»5«/mn»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»is«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»equal«/mi»«mo»§nbsp;«/mo»«mi mathvariant=¨normal¨»to«/mi»«/math»
a. 0
b. 1
c. 2
d. 3
Answer. a
7. The sum and difference of two expression are «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mn»5«/mn»«msup»«mi»x«/mi»«mn»2«/mn»«/msup»«mo»-«/mo»«mi»x«/mi»«mo»-«/mo»«mn»4«/mn»«/math» and «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»x«/mi»«mn»2«/mn»«/msup»«mo»+«/mo»«mn»9«/mn»«mi»x«/mi»«mo»-«/mo»«mn»10«/mn»«/math» respectively. The HCF of two expressions will be
a. (x+1)
b. (x-1)
c. (3x+7)
d. (2x-3)
Answer. b
8. If (s-a)+(s-b)+(s-c) = s, then the value of Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mrow»«mo»(«/mo»«mi»s«/mi»«mo»-«/mo»«mi»a«/mi»«msup»«mo»)«/mo»«mn»2«/mn»«/msup»«mo»+«/mo»«mo»(«/mo»«mi»s«/mi»«mo»-«/mo»«mi»b«/mi»«msup»«mo»)«/mo»«mn»2«/mn»«/msup»«mo»+«/mo»«mo»(«/mo»«mi»s«/mi»«mo»-«/mo»«mi»c«/mi»«msup»«mo»)«/mo»«mn»2«/mn»«/msup»«mo»+«/mo»«msup»«mi»s«/mi»«mn»2«/mn»«/msup»«/mrow»«mrow»«msup»«mi»a«/mi»«mn»2«/mn»«/msup»«mo»+«/mo»«msup»«mi»b«/mi»«mn»2«/mn»«/msup»«mo»+«/mo»«msup»«mi»c«/mi»«mn»2«/mn»«/msup»«/mrow»«/mfrac»«/math» will be
a. 3
b. 1
c. 0
d. -1
Answer. b
9.  Â«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnalign=¨left¨ rowspacing=¨0¨»«mtr»«mtd»«mi mathvariant=¨normal¨»if«/mi»«moȤnbsp;«/mo»«mi mathvariant=¨normal¨»the«/mi»«moȤnbsp;«/mo»«mi mathvariant=¨normal¨»polynomial«/mi»«moȤnbsp;«/mo»«msup»«mi mathvariant=¨normal¨»x«/mi»«mn»6«/mn»«/msup»«mo»+«/mo»«msup»«mi mathvariant=¨normal¨»px«/mi»«mn»5«/mn»«/msup»«mo»+«/mo»«msup»«mi mathvariant=¨normal¨»qx«/mi»«mn»4«/mn»«/msup»«mo»-«/mo»«msup»«mi mathvariant=¨normal¨»x«/mi»«mn»2«/mn»«/msup»«mo»-«/mo»«mi mathvariant=¨normal¨»x«/mi»«mo»-«/mo»«mn»3«/mn»«moȤnbsp;«/mo»«mi mathvariant=¨normal¨»is«/mi»«moȤnbsp;«/mo»«mi mathvariant=¨normal¨»divisible«/mi»«moȤnbsp;«/mo»«mi mathvariant=¨normal¨»by«/mi»«moȤnbsp;«/mo»«mo»(«/mo»«msup»«mi mathvariant=¨normal¨»x«/mi»«mn»4«/mn»«/msup»«mo»-«/mo»«mn»1«/mn»«mo»)«/mo»«mo»,«/mo»«moȤnbsp;«/mo»«/mtd»«/mtr»«mtr»«mtd»«mi mathvariant=¨normal¨»th«/mi»«mi mathvariant=¨normal¨»en«/mi»«moȤnbsp;«/mo»«mi mathvariant=¨normal¨»the«/mi»«moȤnbsp;«/mo»«mi mathvariant=¨normal¨»value«/mi»«moȤnbsp;«/mo»«mi mathvariant=¨normal¨»of«/mi»«moȤnbsp;«/mo»«msup»«mi mathvariant=¨normal¨»p«/mi»«mn»2«/mn»«/msup»«mo»+«/mo»«msup»«mi mathvariant=¨normal¨»q«/mi»«mn»2«/mn»«/msup»«moȤnbsp;«/mo»«mi mathvariant=¨normal¨»is«/mi»«/mtd»«/mtr»«/mtable»«/math»
a. 1
b. 9
c. 10
d. 13
Answer. c
10. Let p and q be non-zero integers. Consider the polynomial A(x) = x^2 + px+q It is given that (x – m) and (x – km) are simple factors of A(x), where m is a non-zero integer and k is a positive integer, k ≥ 2. Which one of the following is correct?
a. cds22016mathq10a
b. cds22016mathq10b
c. cds22016mathq10c
d. cds22016mathq10d
Answer. b

Leave Your Comment

Related Posts

Recent Posts